Please describe the problem:
If a static const variable is generated at initialization time via code, it can't be used as a case label as expected.  It appears this is because the .c code is a macro, so the case label expands to a line of code.

Steps to reproduce:

static const int ONE = "1".to_int();
static const int TWO = "2".to_int();

void main() {
    int foo = 1;
    switch (foo) {
        case ONE:
            stdout.printf("one\n");
        break;
        
        case TWO:
            stdout.printf("two\n");
        break;
        
        default:
            stdout.printf("unknown\n");
        break;
    }
}

Note that because of the macro technique, this *does* work in place of the switch block:

    if (foo == ONE) {
        stdout.printf("one\n");
    } else if (foo == TWO) {
        stdout.printf("two\n");
    } else {
        stdout.printf("unknown\n");
    }


Actual results:
The above code produces the compiler error "case label does not reduce to an integer constant".

Expected results:


Does this happen every time?


Other information: