When a delegate is taking an out parameter like that one:

|public delegate void SampleFunc (int a, out int x);

then the lambda will be broken wrt the out parameter. The generated CCode will have within the callback a parameter "gint x" instead of "gint *x". If instead of using a lambda, you use a function everything is fine (as long as you specify the out parameter of course).

|void f1 (int a, out int x) {
|       print ("a %d\n", a);
|       x = a * 10;
|}


Here is a sample that uses the same code in the function callback and in the lamdba:

public delegate void SampleFunc (int a, out int x);

void f1 (int a, out int x) {
       print ("a %d\n", a);
       x = a * 10;
}

void f2 (SampleFunc func, int a) {
       int x;
       func (a, out x);
       print ("x %d\n", x);
}

static int main (string[] args) {
       /* Passing a function */
       f2 (f1, 5);
       /* Using a lambda */
       f2 ( (a, x) => {
               print ("lambda a %d\n", a);
               x = a * 10;
               }, 5);
       return 0;
}